2019届高三数学上学期期中联考试题 理
第Ⅰ卷(选择题 共60分)
一、选择题(本大题共12个小题,每个小题5分,满分60分.每个小题的四个选项中,只有一项符合要求)
1.已知集合d41d8cd98f00b204e9800998ecf8427e.png是整数集,则d41d8cd98f00b204e9800998ecf8427e.png
d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png
2.若复数d41d8cd98f00b204e9800998ecf8427e.png为纯虚数,其中则d41d8cd98f00b204e9800998ecf8427e.png的值为
d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png
3.在△ABC中,若4b72fa6a8513094d3ffa6b00db57ffb3.png,则131516d560f6197c667fa60b3d7576aa.png=
A 78aa3b8f265995f9d47ba3a99ae56c8d.png B.9c20cb9648f6127a648f79bc920a354f.png
C.db2c55ca23352c301366ad400a9480be.png D.9bed49bcaa3c45909ae02ee4a24b757a.png
4.已知命题d41d8cd98f00b204e9800998ecf8427e.png则有关命题d41d8cd98f00b204e9800998ecf8427e.png的真假及d41d8cd98f00b204e9800998ecf8427e.png的论述正确的是
d41d8cd98f00b204e9800998ecf8427e.png假命题,d41d8cd98f00b204e9800998ecf8427e.png
d41d8cd98f00b204e9800998ecf8427e.png真命题,d41d8cd98f00b204e9800998ecf8427e.png
d41d8cd98f00b204e9800998ecf8427e.png假命题,d41d8cd98f00b204e9800998ecf8427e.png
d41d8cd98f00b204e9800998ecf8427e.png真命题,d41d8cd98f00b204e9800998ecf8427e.png
5.函数d41d8cd98f00b204e9800998ecf8427e.png的最小正周期为
d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png
6.向量89e9c902fed032a267e19bcbbe710b75.png,7f711ac1314a21599dc5a9c5bb757eff.png均为非零向量,bad825d6aed822782a534ce7161014d7.png,则89e9c902fed032a267e19bcbbe710b75.png,7f711ac1314a21599dc5a9c5bb757eff.png的夹角为
A.d41d8cd98f00b204e9800998ecf8427e.png B.d41d8cd98f00b204e9800998ecf8427e.png C.d41d8cd98f00b204e9800998ecf8427e.png D.d41d8cd98f00b204e9800998ecf8427e.png
7. 为了得到函数d41d8cd98f00b204e9800998ecf8427e.png的图像,可以将函数d41d8cd98f00b204e9800998ecf8427e.png的图像( )
A. 向左平移d41d8cd98f00b204e9800998ecf8427e.png个单位 B. 向右平移d41d8cd98f00b204e9800998ecf8427e.png个单位
C. 向右平移d41d8cd98f00b204e9800998ecf8427e.png个单位 D. 向左平移d41d8cd98f00b204e9800998ecf8427e.png个单位
8. 函数word/media/image44_1.png的图象可能是
(A) (B) (C) (D)
9. 已知定义在d41d8cd98f00b204e9800998ecf8427e.png上的函数d41d8cd98f00b204e9800998ecf8427e.png满足:①对于任意的d41d8cd98f00b204e9800998ecf8427e.png,都有d41d8cd98f00b204e9800998ecf8427e.png;②函数d41d8cd98f00b204e9800998ecf8427e.png是偶函数;③当d41d8cd98f00b204e9800998ecf8427e.png时,d41d8cd98f00b204e9800998ecf8427e.png,设d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,则d41d8cd98f00b204e9800998ecf8427e.png的大小关系是 ( )
A.d41d8cd98f00b204e9800998ecf8427e.png B.d41d8cd98f00b204e9800998ecf8427e.png C.d41d8cd98f00b204e9800998ecf8427e.png D.d41d8cd98f00b204e9800998ecf8427e.png
10.已知函数d41d8cd98f00b204e9800998ecf8427e.png,且d41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.png,则函数d41d8cd98f00b204e9800998ecf8427e.png图象的一条对称轴的方程为( )
A.d41d8cd98f00b204e9800998ecf8427e.png B. d41d8cd98f00b204e9800998ecf8427e.png C.d41d8cd98f00b204e9800998ecf8427e.png D. d41d8cd98f00b204e9800998ecf8427e.png
11.若定义在d41d8cd98f00b204e9800998ecf8427e.png上的函数d41d8cd98f00b204e9800998ecf8427e.png满足d41d8cd98f00b204e9800998ecf8427e.png则不等式d41d8cd98f00b204e9800998ecf8427e.png的解集为
d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png
12. 已知函数d41d8cd98f00b204e9800998ecf8427e.png,若d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png恒成立,则实数d41d8cd98f00b204e9800998ecf8427e.png的取值范围是(A)d41d8cd98f00b204e9800998ecf8427e.png (B)d41d8cd98f00b204e9800998ecf8427e.png (C)d41d8cd98f00b204e9800998ecf8427e.png (D)d41d8cd98f00b204e9800998ecf8427e.png
第II卷(非选择题 共90分)
二、填空题:本小题共4个小题,每小题5分,满分20分.
13. 设d41d8cd98f00b204e9800998ecf8427e.png为锐角,若d41d8cd98f00b204e9800998ecf8427e.png,则d41d8cd98f00b204e9800998ecf8427e.png的值为
14.已知向量d41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.png,且d41d8cd98f00b204e9800998ecf8427e.png在d41d8cd98f00b204e9800998ecf8427e.png上的投影为d41d8cd98f00b204e9800998ecf8427e.png,则向量d41d8cd98f00b204e9800998ecf8427e.png与d41d8cd98f00b204e9800998ecf8427e.png夹角为_________.
15.若定义在[-1,+∞)上的函数f(x)=d41d8cd98f00b204e9800998ecf8427e.png,则d41d8cd98f00b204e9800998ecf8427e.png=_____
16、已知定义在R上的函数word/media/image101_1.png满足:word/media/image102_1.png,
word/media/image103_1.png,则方程word/media/image104_1.png在区间word/media/image105_1.png上的所有实根之和为
三、本大题共6小题,共70分,解答应写出必要的文字说明、证明过程或演算步骤.
17.(本小题满分12分)
已知三个集合:word/media/image106_1.png,word/media/image107_1.png,
word/media/image108_1.png.
(1)求word/media/image109_1.png;
(2)已知word/media/image110_1.png,求实数word/media/image111_1.png的取值范围.
18.(本小题满分12分)
已知向量word/media/image112_1.png,word/media/image113_1.png word/media/image114_1.png,设函数word/media/image115_1.png.
(1)求函数word/media/image116_1.png的单调增区间;
(2)已知word/media/image117_1.png的三个内角分别为word/media/image118_1.png若word/media/image119_1.png,word/media/image120_1.png,边word/media/image121_1.png,
求边word/media/image122_1.png.
19.(本题满分12分)
已知函数549b52d88f673b03d4d4dd5cdd6fbb9e.png.
(1)求函数d41d8cd98f00b204e9800998ecf8427e.png的图象在点d41d8cd98f00b204e9800998ecf8427e.png处的切线d41d8cd98f00b204e9800998ecf8427e.png的方程;
(2)讨论函数d41d8cd98f00b204e9800998ecf8427e.png的单调性.
20.(本小题满分12分)
如图所示,某公路AB一侧有一块空地△OAB,其中OA=3 km,OB=393d65e83547db2535bfb99add1b38d8c.png km,∠AOB=90°.当地政府拟在中间开挖一个人工湖△OMN,其中M,N都在边AB上(M,N不与A,B重合,M在A,N之间),且∠MON=30°.
(1)若M在距离A点2 km处,求点M,N之间的距离;
(2)为节省投入资金,人工湖△OMN的面积要尽可能小.试确定M的位置,使△OMN的面积最小,并求出最小面积.
21. (本小题满分12分)
已知函数word/media/image129_1.png.
(1)求曲线word/media/image130_1.png在点word/media/image131_1.png处的切线方程;
(2)是否存在正整数word/media/image132_1.png,使函数word/media/image133_1.png在word/media/image134_1.png上单调递增,若存在,求出正整数
word/media/image132_1.png的所有值,若不存在,说明理由.
请考生在第22、23两题中任选一题做答,如果多做.则按所做的第一题记分.做答时请写清题号。
22. (本小题满分10分)选修4-4:极坐标系与参数方程
在直角坐标系xOy中,曲线M的参数方程为85b15cebf5a6e5f6f40a8c28f0589b83.png(α为参数),若以直角坐标系中的原点O为极点,x轴的正半轴为极轴建立极坐标系,曲线N的极坐标方程为c6ae05ceaa05b3aa9a388cd8fc217b85.png(t为参数).
(1)求曲线M的普通方程和曲线N的直角坐标方程;
(2)若曲线N与曲线M有公共点,求t的取值范围.
23.(本小题满分10分)选修4-5:不等式选讲
已知函数d41d8cd98f00b204e9800998ecf8427e.png.
(1)当d41d8cd98f00b204e9800998ecf8427e.png时,求不等式d41d8cd98f00b204e9800998ecf8427e.png的解集;
(2)求证:d41d8cd98f00b204e9800998ecf8427e.png.
理科数学参考答案
1—12 CAADB ABCDC AB
13. ba5cacbaadbfed8096ec2db57214e4c7.png. 14.d41d8cd98f00b204e9800998ecf8427e.png 15.d41d8cd98f00b204e9800998ecf8427e.png 16.-7
17.(本小题满分12分)
解:(1)word/media/image144_1.png, . …………………………………2分
word/media/image145_1.png,. ……………………………………….4分
word/media/image146_1.png. …………………………………………………..………..6分
(2)word/media/image147_1.png,
word/media/image148_1.png ……………………………………………..…….…..7分
word/media/image149_1.png
word/media/image150_1.png ……………………………………………..…..8分
即word/media/image151_1.png解得word/media/image152_1.png ……………………..……..11分
所以实数word/media/image111_1.png的取值范围是word/media/image153_1.png ………………………………………..….12分
18. (本小题满分12分)
解:word/media/image154_1.png word/media/image155_1.pngword/media/image156_1.png.
word/media/image157_1.png …………………………4分 ∵word/media/image158_1.pngword/media/image159_1.pngR,由 word/media/image160_1.png 得
word/media/image161_1.png……… 6分
∴函数word/media/image116_1.png的单调增区间为.word/media/image162_1.png ………………7分
(2)∵word/media/image163_1.png,即word/media/image164_1.png,∵角word/media/image165_1.png为锐角,得word/media/image166_1.png, ……9分
又word/media/image120_1.png,∴word/media/image167_1.png,∴word/media/image168_1.png
∵word/media/image121_1.png,由正弦定理得word/media/image169_1.png ……… 12分
19. (本题满分12分)
(1)9f19a63ff8ae7e8beb2a0d7f3ccd5305.png ……………1分
8cdea569e63b0d0656ed79172667dc10.png …………………………2分
369c6c6b44592223dd433f8e9bff0451.png …………………………3分
切线方程:0ac13f40fed6cbbe9cfcb2a3111d8dd4.png 即831d5b482a46219eb0d2faac1e214f35.png……………4分
(2)d41d8cd98f00b204e9800998ecf8427e.png,6c68abddbb494d40844c68b1badb8e29.png……………………5分
令d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,
word/media/image179.gif当d41d8cd98f00b204e9800998ecf8427e.png时,d41d8cd98f00b204e9800998ecf8427e.png,所以d41d8cd98f00b204e9800998ecf8427e.png在d41d8cd98f00b204e9800998ecf8427e.png上单调递增。………6分
word/media/image184.gif当d41d8cd98f00b204e9800998ecf8427e.png时,令d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.png,
所以d41d8cd98f00b204e9800998ecf8427e.png在d41d8cd98f00b204e9800998ecf8427e.png上单调递增,在d41d8cd98f00b204e9800998ecf8427e.png上单调递减。……………9分
word/media/image192.gif当d41d8cd98f00b204e9800998ecf8427e.png时,令d41d8cd98f00b204e9800998ecf8427e.pngd41d8cd98f00b204e9800998ecf8427e.png,d41d8cd98f00b204e9800998ecf8427e.png,
所以d41d8cd98f00b204e9800998ecf8427e.png在d41d8cd98f00b204e9800998ecf8427e.png上单调递减,在d41d8cd98f00b204e9800998ecf8427e.png上单调递增。………………12分
20. (本题满分12分)
解:(1)在△OAB中,因为OA=3,OB=393d65e83547db2535bfb99add1b38d8c.png,∠AOB=90°,所以∠OAB=60°.
在△OAM中,由余弦定理得OM2=AO2+AM2-2AO·AM·cosA=7,
所以OM=93420df375b0cdc9f4d058d0f28cf8fb.png,所以cos∠AOM=702ef391f8bb3d5967fadf91baf8364b.png=d9ea467160ff4f0242c2ac1955b93697.png93420df375b0cdc9f4d058d0f28cf8fb.png,
在△OAN中,sin∠ONA=sin(∠A+∠AON)= sin(∠AOM+90°)=cos∠AOM=d9ea467160ff4f0242c2ac1955b93697.png93420df375b0cdc9f4d058d0f28cf8fb.png.
在△OMN中,由557473b6405e8dac96d6c230dd41a4a9.png=1ca60f50cc627678283a5d820cfea5aa.png,得MN=2d3c38dc88581b8d4ec4536c8a1a151b.png93420df375b0cdc9f4d058d0f28cf8fb.pngd9ea467160ff4f0242c2ac1955b93697.png93420df375b0cdc9f4d058d0f28cf8fb.png×df4344a8d214cca83c5817f341d32b3d.png=59277bfaba258555f7c1c2ee38383247.png. ………6分
(2):设∠AOM=θ,0<θ<7e64500b7eb14f2abb038336939271b1.png
在△OAM中,由6288f0cc19625f5cea1e0ab85419751a.png=5f29693583fddfaa19a531d96702cd4e.png,得OM=6f451c8be23f418d7f0d2f8b645b20db.png93d65e83547db2535bfb99add1b38d8c.png7e64500b7eb14f2abb038336939271b1.png.
在△OAN中,由08a9bb4ddb6d0e03d4ebd78b5a8b86b7.png=7b7cf904ef4035f2bdb80852d31f2fb5.png,得ON=6f451c8be23f418d7f0d2f8b645b20db.png93d65e83547db2535bfb99add1b38d8c.png5522d5e7ec715af7dda4102fd0415431.png=6f451c8be23f418d7f0d2f8b645b20db.png93d65e83547db2535bfb99add1b38d8c.png.
所以S△OMN=df4344a8d214cca83c5817f341d32b3d.pngOM·ON·sin∠MON=df4344a8d214cca83c5817f341d32b3d.png·6f451c8be23f418d7f0d2f8b645b20db.png93d65e83547db2535bfb99add1b38d8c.png7e64500b7eb14f2abb038336939271b1.png·6f451c8be23f418d7f0d2f8b645b20db.png93d65e83547db2535bfb99add1b38d8c.png·df4344a8d214cca83c5817f341d32b3d.png
=5b92fbc04c8be1d4d0619077c0ccd8dd.png7e64500b7eb14f2abb038336939271b1.png=28c52cdd2427f707331556de8bb3da33.png93d65e83547db2535bfb99add1b38d8c.png=946c791f8d8b353dd7c42256a9471044.png93d65e83547db2535bfb99add1b38d8c.png93d65e83547db2535bfb99add1b38d8c.png
=946c791f8d8b353dd7c42256a9471044.png93d65e83547db2535bfb99add1b38d8c.png93d65e83547db2535bfb99add1b38d8c.png=b46ea622f97e376e0e1196fd55fc1724.png7e64500b7eb14f2abb038336939271b1.png93d65e83547db2535bfb99add1b38d8c.png,0<θ<7e64500b7eb14f2abb038336939271b1.png.
当2θ+7e64500b7eb14f2abb038336939271b1.png=5522d5e7ec715af7dda4102fd0415431.png,即θ=2929ea5b0891b637ab959788a75ad228.png时,S△OMN的最小值为9df4a5f402479e4940fd7999778aa3d1.png93d65e83547db2535bfb99add1b38d8c.png.
所以应设计∠AOM=2929ea5b0891b637ab959788a75ad228.png,可使△OMN的面积最小,最小面积是9df4a5f402479e4940fd7999778aa3d1.png93d65e83547db2535bfb99add1b38d8c.png km2.----------12分
21.解:
(1):由已知word/media/image199_1.png得word/media/image200_1.png, ---------1分
word/media/image201_1.png得word/media/image202_1.png. --------2分
word/media/image203_1.png在word/media/image204_1.png处的切线方程为word/media/image205_1.png即word/media/image206_1.png ---5分
(2)法一:令word/media/image207_1.png,依题意word/media/image208_1.png在word/media/image209_1.png上恒成立, word/media/image210_1.png. ------7分
1 当word/media/image211_1.png时,word/media/image212_1.png ,word/media/image213_1.png在word/media/image214_1.png上单调递增, word/media/image215_1.png
2 故word/media/image216_1.png符合题意 --------9分
3 当word/media/image217_1.png时,由word/media/image218_1.png得word/media/image219_1.png. word/media/image220_1.png取值变化情况如下表,
依题意word/media/image227_1.png即word/media/image228_1.png. -------------------------10分
令word/media/image229_1.png,则word/media/image230_1.png,word/media/image231_1.png在word/media/image232_1.png上单调递减,
由word/media/image233_1.png,word/media/image234_1.png知word/media/image235_1.png时,word/media/image236_1.png,故此时只有word/media/image237_1.png符合题意.
综上,所求正整数word/media/image238_1.png的值有1,2,3. ----------12分
法二:
由word/media/image239_1.png在word/media/image240_1.png上恒成立,得word/media/image241_1.png在word/media/image242_1.png上恒成立。---6分
令word/media/image243_1.pngword/media/image244_1.png,则word/media/image245_1.png, ---------7分
令word/media/image246_1.png,得word/media/image247_1.png在word/media/image248_1.png上恒成立, ----8分
又word/media/image249_1.png,[
从而word/media/image250_1.png,使word/media/image251_1.png,即word/media/image252_1.png。 ---------10分
进而知word/media/image253_1.png取值变化情况如下表,
word/media/image259_1.pngword/media/image260_1.pngword/media/image261_1.png故符合题意的正整数K为1,2,3. -------------12分
22解 (1)由x=cosα+sinα得x2=(cosα+sinα)2=cos2α+2sinαcosα+sin2α,
所以曲线M可化为y=x2-1,aa777495bd5cda3ceec2906644d486a5.png,
由ρsinc61c1e8442e7a73317433d8b0c3cabbd.png=193acac34cd52a51c1973c3ce22b6172.pngt得193acac34cd52a51c1973c3ce22b6172.pngρsinθ+193acac34cd52a51c1973c3ce22b6172.pngρcosθ=193acac34cd52a51c1973c3ce22b6172.pngt,
所以ρsinθ+ρcosθ=t,所以曲线N可化为x+y=t.
(2)若曲线M,N有公共点,则当直线N过点6bac7945dbe12bc5b826168e2cbbca8b.png,时满足要求,此时t=4bc3c43b38c136cb7a40b233c50b591e.png,并且向左下方平行移动直到相切之前总有公共点,相切时仍然只有一个公共点,
联立bbfe92bcd36e651208b935836546e762.png,得x2+x-1-t=0,
由Δ=1+4(1+t)=0,解得t=-9d3355dd2ffe42827c14804d953fb335.png.
综上可求得t的取值范围是-9d3355dd2ffe42827c14804d953fb335.png≤t≤4bc3c43b38c136cb7a40b233c50b591e.png
23.解:(1)当a=2时,d41d8cd98f00b204e9800998ecf8427e.png原不等式等价于
d41d8cd98f00b204e9800998ecf8427e.png
解得d41d8cd98f00b204e9800998ecf8427e.png故不等式d41d8cd98f00b204e9800998ecf8427e.png的解集是d41d8cd98f00b204e9800998ecf8427e.png
(2)证明:d41d8cd98f00b204e9800998ecf8427e.png
d41d8cd98f00b204e9800998ecf8427e.png d41d8cd98f00b204e9800998ecf8427e.png
当且仅当d41d8cd98f00b204e9800998ecf8427e.png时等号成立。
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